- ral-insert! ls place itemprocedure
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command ((oldcount newcount (lambda (ls place item) (ral-count ls))) (olditem newitem (lambda (ls place item) (ral-ref ls place)))) requires (and (ral? ls) ((ral-item? ls) item) (fixnum? place) (fx>= place 0) (fx<= place (ral-count ls))) ensures (and (fx= newcount (fx+ 1 oldcount)) (equal? newitem item))